task: #1965

Author: Ivanbyone

README.md

@@ -60,6 +60,7 @@ Have a good contributing!
     - [1693. Daily Leads and Partners](./leetcode/easy/1693.%20Daily%20Leads%20and%20Partners.sql)
     - [1729. Find Followers Count](./leetcode/easy/1729.%20Find%20Followers%20Count.sql)
     - [1741. Find Total Time Spent by Each Employee](./leetcode/easy/1741.%20Find%20Total%20Time%20Spent%20by%20Each%20Employee.sql)
+    - [1965. Employees With Missing Information](./leetcode/easy/1965.%20Employees%20With%20Missing%20Information.sql)
 2. [Medium](./leetcode/medium/)
     - [176. Second Highest Salary](./leetcode/medium/176.%20Second%20Highest%20Salary.sql)
     - [184. Department Highest Salary](./leetcode/medium/184.%20Department%20Highest%20Salary.sql)

leetcode/easy/1965. Employees With Missing Information.sql

@@ -0,0 +1,53 @@
+/*
+Question 1965. Employees With Missing Information
+Link: https://leetcode.com/problems/employees-with-missing-information/description/
+
+Table: Employees
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| employee_id | int     |
+| name        | varchar |
++-------------+---------+
+employee_id is the column with unique values for this table.
+Each row of this table indicates the name of the employee whose ID is employee_id.
+ 
+
+Table: Salaries
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| employee_id | int     |
+| salary      | int     |
++-------------+---------+
+employee_id is the column with unique values for this table.
+Each row of this table indicates the salary of the employee whose ID is employee_id.
+ 
+
+Write a solution to report the IDs of all the employees with missing information. The information of an employee is missing if:
+
+The employee's name is missing, or
+The employee's salary is missing.
+Return the result table ordered by employee_id in ascending order.
+*/
+
+WITH all_employees AS (
+    SELECT employee_id
+    FROM Employees
+    UNION
+    SELECT employee_id
+    FROM Salaries
+)
+
+SELECT a.employee_id 
+FROM all_employees AS a
+LEFT JOIN 
+    Employees AS e
+    ON a.employee_id = e.employee_id
+LEFT JOIN 
+    Salaries AS s
+    ON a.employee_id = s.employee_id
+WHERE e.name IS NULL OR s.salary IS NULL
+ORDER BY a.employee_id ASC