task: #181

Author: Ivanbyone

.sqlfluff

@@ -4,4 +4,4 @@ exclude_rules = LT01, CP02
 
 [sqlfluff:rules]
 keywords_capitalisation_policy = upper
-max_line_length = 100
+max_line_length = 120

README.md

@@ -1,7 +1,7 @@
 # Leetcode (PostgreSQL)
 
 [![MIT licensed](https://img.shields.io/badge/License-MIT-yellow.svg)](./LICENSE)
-[![CI](https://github.com/ivanbyone/hookify/actions/workflows/ci.yml/badge.svg)](https://github.com/Ivanbyone/leetcode-sql//actions)
+[![CI](https://github.com/ivanbyone/leetcode-sql/actions/workflows/ci.yml/badge.svg)](https://github.com/Ivanbyone/leetcode-sql//actions)
 
 ## Description
 
@@ -33,8 +33,9 @@ Have a good contributing!
 ## Task List
 
 1. [Easy](./leetcode/easy/)
-    - [182. Duplicate Emails](./leetcode/easy/182.%20Duplicate%20Emails.sql)
     - [175. Combine Two Tables](./leetcode//easy/175.%20Combine%20Two%20Tables.sql)
+    - [181. Employees Earning More Than Their Managers](./leetcode/easy/181.%20Employees%20Earning%20More%20Than%20Their%20Managers.sql)
+    - [182. Duplicate Emails](./leetcode/easy/182.%20Duplicate%20Emails.sql)
     - [183. Customers Who Never Order](./leetcode/easy/183.%20Customers%20Who%20Never%20Order.sql)
     - [511. Game Play Analysis 1](./leetcode/easy/511.%20Game%20Play%20Analysis%201.sql)
     - [595. Big Countries](./leetcode/easy/595.%20Big%20Countries.sql)

leetcode/easy/181. Employees Earning More Than Their Managers.sql

@@ -0,0 +1,31 @@
+/*
+Question 181. Employees Earning More Than Their Managers
+Link: 
+https://leetcode.com/problems/employees-earning-more-than-their-managers/description/
+
+Table: Employee
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| id          | int     |
+| name        | varchar |
+| salary      | int     |
+| managerId   | int     |
++-------------+---------+
+id is the primary key (column with unique values) for this table.
+Each row of this table indicates the ID of an employee, 
+their name, salary, and the ID of their manager.
+ 
+
+Write a solution to find the employees who earn more 
+than their managers.
+
+Return the result table in any order.
+*/
+
+SELECT t1.name AS Employee
+FROM Employee t1
+JOIN Employee t2
+    ON t1.managerId = t2.id
+WHERE t1.salary > t2.salary