task: #1633

Author: Ivanbyone

README.md

@@ -51,6 +51,7 @@ Have a good contributing!
     - [1407. Top Travellers](./leetcode/easy/1407.%20Top%20Travellers.sql)
     - [1484. Group Sold Products By The Date](./leetcode/easy/1484.%20Group%20Sold%20Products%20By%20The%20Date.sql)
     - [1587. Bank Account Summary II](./leetcode/easy/1587.%20Bank%20Account%20Summary%20II.sql)
+    - [1633. Percentage of Users Attended a Contest](./leetcode/easy/1633.%20Percentage%20of%20Users%20Attended%20a%20Contest.sql)
     - [1693. Daily Leads and Partners](./leetcode/easy/1693.%20Daily%20Leads%20and%20Partners.sql)
     - [1729. Find Followers Count](./leetcode/easy/1729.%20Find%20Followers%20Count.sql)
     - [1741. Find Total Time Spent by Each Employee](./leetcode/easy/1741.%20Find%20Total%20Time%20Spent%20by%20Each%20Employee.sql)

leetcode/easy/1633. Percentage of Users Attended a Contest.sql

@@ -0,0 +1,39 @@
+/*
+Question 1633. Percentage of Users Attended a Contest
+Link: https://leetcode.com/problems/percentage-of-users-attended-a-contest/
+
+Table: Users
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| user_id     | int     |
+| user_name   | varchar |
++-------------+---------+
+user_id is the primary key (column with unique values) for this table.
+Each row of this table contains the name and the id of a user.
+ 
+
+Table: Register
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| contest_id  | int     |
+| user_id     | int     |
++-------------+---------+
+(contest_id, user_id) is the primary key (combination of columns with unique values) for this table.
+Each row of this table contains the id of a user and the contest they registered into.
+ 
+
+Write a solution to find the percentage of the users registered in each contest rounded to two decimals.
+
+Return the result table ordered by percentage in descending order. In case of a tie, order it by contest_id in ascending order.
+*/
+
+SELECT 
+    contest_id,
+    ROUND(COUNT(contest_id) * 1.0 / (SELECT COUNT(u.user_id) FROM Users AS u) * 100, 2) AS percentage
+FROM Register
+GROUP BY contest_id
+ORDER BY percentage DESC, contest_id ASC