task: #570

Author: Ivanbyone

README.md

@@ -57,6 +57,7 @@ Have a good contributing!
 2. [Medium](./leetcode/medium/)
     - [176. Second Highest Salary](./leetcode/medium/176.%20Second%20Highest%20Salary.sql)
     - [184. Department Highest Salary](./leetcode/medium/184.%20Department%20Highest%20Salary.sql)
+    - [570. Managers with at Least 5 Direct Reports](./leetcode/medium/570.%20Managers%20with%20at%20Least%205%20Direct%20Reports.sql)
     - [602. Friend Requests II: Who Has the Most Friends](./leetcode/medium/602.%20Friend%20Requests%20II:%20Who%20Has%20the%20Most%20Friends.sql)
     - [1045. Customers Who Bought All Products](./leetcode/medium/1045.%20Customers%20Who%20Bought%20All%20Products.sql)
     - [1070. Product Sales Analysis III](./leetcode/medium/1070.%20Product%20Sales%20Analysis%203.sql)

leetcode/medium/570. Managers with at Least 5 Direct Reports.sql

@@ -0,0 +1,39 @@
+/*
+Question 570. Managers with at Least 5 Direct Reports
+Link: https://leetcode.com/problems/managers-with-at-least-5-direct-reports/description/
+
+Table: Employee
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| id          | int     |
+| name        | varchar |
+| department  | varchar |
+| managerId   | int     |
++-------------+---------+
+id is the primary key (column with unique values) for this table.
+Each row of this table indicates the name of an employee, their department, and the id of their manager.
+If managerId is null, then the employee does not have a manager.
+No employee will be the manager of themself.
+ 
+
+Write a solution to find managers with at least five direct reports.
+
+Return the result table in any order.
+*/
+
+WITH five_direct AS (
+    SELECT 
+        managerId, 
+        COUNT(managerId) AS manager
+    FROM Employee
+    GROUP BY managerId
+)
+
+SELECT e.name 
+FROM Employee AS e
+LEFT JOIN 
+    five_direct AS f
+    ON e.id = f.managerId
+WHERE f.manager >= 5